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Inflation calculator - US Dollar

$6,300 in 1989
$10,244.91 in 2006

The inflation rate in the United States between 1989 and 2006 was 62.62%, which translates into a total increase of $3,944.91. This means that 6,300 dollars in 1989 are equivalent to 10,244.91 dollars in 2006. In other words, the purchasing power of $6,300 in 1989 equals $10,244.91 in 2006. The average annual inflation rate between these periods was 2.9%.

Inflation timeline in the United States (1989 - 2006)

The following chart depicts the equivalence of $6,300 due to compound inflation and CPI changes. All values are equivalent in terms of purchasing power, which means that for each year the same goods or services could be bought with the indicated amount of money.

$11k$11k$10k$10k$9k$9k$8k$8k$7k$7k$6k$6k1989198919901990199119911992199219931993199419941995199519961996199719971998199819991999200020002001200120022002200320032004200420052005

All calculations are performed in the local currency (USD) and using 6 decimal digits. Results show only up to 2 decimal digits to favour readability. Inflation data is provided by governments and international institutions on a monthly basis.

The following table contains relevant indicators:

Indicator Value
Cumulative inflation from 1989 to 2006 62.62%
Avg. Annual inflation from 1989 to 2006 2.9%
CPI 1989 123.97
CPI 2006 201.59

How to calculate the time value of money with inflation data?

There are several ways to calculate the time value of money. Depending on the data available, results can be obtained by using the Consumer Price Index (CPI) formula or the compound interest formula.

Using the CPI formula

When we have both the start and end years, we can use the following formula:

Valuet =Value0 ×
CPIt/CPI0

To obtain the values equivalent in buying power between 1989 and 2006, use the corresponding CPI values:

Value2006
=Value1989 ×
CPI2006/CPI1989
=$ 6,300 ×
201.59/123.97
$10,244.91

Alternative: Using the compound interest formula

Given that money changes with time as a result of an inflation rate that acts as compound interest, we can use the following formula: FV = PV × (1 + i)n, where:

  • FV: Future Value
  • PV: Present Value
  • i: Interest rate (inflation)
  • n: Number of times the interest is compounded (i.e. # of years)

In this case, the future value represents the final amount obtained after applying the inflation rate to our initial value. In other words, it indicates how much are $6,300 worth today. There are 17 years between 1989 and 2006 and the average inflation rate was 2.9015%. Therefore, we can resolve the formula like this:

Value2006
=PV × (1 + i)n
=$6,300 × (1 + 0.029015)17
$10,244.91

US inflation - Conversion table

Initial Value Equivalent value
$1 dollar in 1989 $1.63 dollars in 2006
$5 dollars in 1989 $8.13 dollars in 2006
$10 dollars in 1989 $16.26 dollars in 2006
$50 dollars in 1989 $81.31 dollars in 2006
$100 dollars in 1989 $162.62 dollars in 2006
$500 dollars in 1989 $813.09 dollars in 2006
$1,000 dollars in 1989 $1,626.18 dollars in 2006
$5,000 dollars in 1989 $8,130.88 dollars in 2006
$10,000 dollars in 1989 $16,261.76 dollars in 2006
$50,000 dollars in 1989 $81,308.82 dollars in 2006
$100,000 dollars in 1989 $162,617.64 dollars in 2006
$500,000 dollars in 1989 $813,088.2 dollars in 2006
$1,000,000 dollars in 1989 $1,626,176.39 dollars in 2006
Cumulative inflation 1989-2006 62.62%
Avg. annual inflation 1989-2006 2.9%
CPI 1989 123.97
CPI 2006 201.59

Value of Dollar over time (by year)

Period Value
1989 6,300
1990 6,640.07
1991 6,921.28
1992 7,130.91
1993 7,341.39
1994 7,532.81
1995 7,744.14
1996 7,971.13
1997 8,157.48
1998 8,284.1
1999 8,465.36
2000 8,751.22
2001 8,998.55
2002 9,141.27
2003 9,348.78
2004 9,599.07
2005 9,924.74
2006 10,244.91

All available years

Today's value of US dollars by year:

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